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Calculate the magnitude of the electric force between a +30uC and -20uC point charges with a mass of 0.05g at a distance of 65.5cm.

Question

Calculate the magnitude of the electric force between a +30uC and -20uC point charges with a mass of 0.05g at a distance of 65.5cm.

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Solution

Sure, to calculate the magnitude of the electric force between two charges, we can use Coulomb's Law, which states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula is:

F = k * |q1*q2| / r^2

where:

  • F is the magnitude of the force between the charges,
  • k is Coulomb's constant (approximately 8.99*10^9 N.m^2/C^2),
  • q1 and q2 are the amounts of charge (in Coulombs),
  • r is the distance between the charges (in meters).

Given: q1 = +30uC = +3010^-6 C (since 1uC = 10^-6 C), q2 = -20uC = -2010^-6 C, r = 65.5cm = 0.655 m (since 1cm = 0.01m).

We can now substitute these values into the formula:

F = 8.9910^9 * |(+3010^-6)(-2010^-6)| / (0.655)^2 = 8.9910^9 * 60010^-12 / 0.429025 = 8.9910^9 * 1.410^-9 = 12.586 N

So, the magnitude of the electric force between the charges is approximately 12.586 Newtons.

This problem has been solved

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