A downward electric force of 5.2N5.2N is exerted on a −7.0μC−7.0𝜇C charge.Part AFind the magnitude of the electric field at the position of this charge.
Question
Solution 1
The electric field (E) is defined as the force (F) per unit charge (q). This can be mathematically represented as:
E = F/q
Given in the problem, we have:
F = 5.2 N (the force on the charge) q = -7.0 μC = -7.0 x 10^-6 C (the charge itself, converted to Coulombs)
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