A downward electric force of 5.2N5.2N is exerted on a −7.0μC−7.0𝜇C charge.Part AFind the magnitude of the electric field at the position of this charge.
Question
A downward electric force of 5.2N is exerted on a -7.0μC charge.
Part A: Find the magnitude of the electric field at the position of this charge.
Solution
The electric field (E) is defined as the force (F) per unit charge (q). This can be mathematically represented as:
E = F/q
Given in the problem, we have:
F = 5.2 N (the force on the charge) q = -7.0 μC = -7.0 x 10^-6 C (the charge itself, converted to Coulombs)
Substituting these values into the formula, we get:
E = 5.2 N / -7.0 x 10^-6 C
Solving this equation will give us the magnitude of the electric field at the position of the charge.
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