A 4.40 μC charge is subject to a 6.00 mN force due to an electric field. What is the magnitude of the electric field at the location of the charge?
Question
Solution 1
The magnitude of the electric field (E) can be calculated using the formula:
E = F/q
where: F is the force = 6.00 mN = 6.00 x 10^-3 N (since 1mN = 10^-3 N) q is the charge = 4.40 μC = 4.40 x 10^-6 C (since 1μC = 10^-6 C)
Substituting the values into the formula, we get:
E = (6.00 x 10^-3 N) / (4 Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
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