f the average of m numbers is n2 and that of n numbers is m2, find the average of (m+n) numbersnmm2nmnn2m

The question seems to be a bit jumbled, but I believe you're asking for the average of (m+n) numbers given that the average of m numbers is n^2 and the average of n numbers is m^2.

Let's break it down:

1. The sum of m numbers is m*n^2 (since average = sum/number of items)
2. The sum of n numbers is n*m^2

To find the average of (m+n) numbers, we first need to find the sum of these (m+n) numbers.

The sum of (m+n) numbers is the sum of m numbers plus the sum of n numbers, which is mn^2 + nm^2.

Now, to find the average of these (m+n) numbers, we divide the sum by the number of items, which is (m+n).

So, the average of (m+n) numbers is (mn^2 + nm^2) / (m+n).