Knowee
Questions
Features
Study Tools

The displacement of particle perforing SHM is given by x=20 cos10t. the amplitude of particle is

Question

The displacement of particle performing SHM is given by

x=20cos(10t) x = 20 \cos(10t)

The amplitude of the particle is:

🧐 Not the exact question you are looking for?Go ask a question

Solution

1. Break Down the Problem

We need to identify the amplitude of a particle performing Simple Harmonic Motion (SHM) from the given displacement equation.

2. Relevant Concepts

In SHM, the displacement of a particle can be expressed in the form: x(t)=Acos(ωt+ϕ) x(t) = A \cos(\omega t + \phi) where:

  • A A = amplitude
  • ω \omega = angular frequency
  • ϕ \phi = phase constant

3. Analysis and Detail

The given displacement equation is: x=20cos(10t) x = 20 \cos(10t) From this equation:

  • We can see that the coefficient of the cosine function (20) represents the amplitude A A .

4. Verify and Summarize

Thus, the amplitude of the particle is directly obtained from the equation.

Final Answer

The amplitude of the particle is 20 20 units.

This problem has been solved

Similar Questions

The displacement of a particle in SHM varies according to the relation x =4(Cos πt + Sin πt). The amplitudeof the particle is

A particle executing SHM has a maximum speed of 30 cm/s and angular frequency of 10 rad/s. Theamplitude of oscillation is

The equation of displacement of a harmonic oscillator is x=3sinωt+4cosωt. The amplitude of the particles will be

What is the wave number of a wave whose displacement, y is defined by the equation y = 25 cos (280t – 75x) in metres?*1 point28/m25/m75/m84/m

What is the amplitude in the equation v = 35 sin(5000t)?Select one:a.5000/π Vb.5000 Vc.35 Vd.35π V

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.