Find the equation of the axis of symmetry of the following parabola algebraically.y, equals, 3, x, squared, minus, 42, x, plus, 156y=3x 2 −42x+156
Question
Solution 1
Para encontrar la ecuación del eje de simetría de la parábola dada ( y = 3x^2 - 42x + 156 ), seguimos estos pasos:
Identificar la forma estándar de la ecuación cuadrática: La ecuación de la parábola está en la forma ( y = ax^2 + bx + c ), donde:
- ( a = 3 )
- ( b = -42 )
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