Surface tension of a soap bubble is 2.0×10−2 N m−1 . Work done to increase the radius of soap bubble from 3.5 cm to 7 cm will be : [Take π=227 ]

Question

Surface tension of a soap bubble is 2.0×10−2 N m−1 . Work done to increase the radius of soap bubble from 3.5 cm to 7 cm will be : [Take π=227 ]
🧐 Not the exact question you are looking for?Go ask a question

Solution 1

The work done to increase the radius of a soap bubble can be calculated using the formula for the work done on a bubble, which is:

W = 8πr₁r₂σ

where:

  • W is the work done,
  • r₁ and r₂ are the initial and final radii of the bubble,
  • σ is the surface tension.

Given:

  • σ = 2.0×10−2 N m−1,
  • r₁ = 3. Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv

This problem has been solved

Similar Questions

Surface tension of a soap bubble is 2.0×10−2 N m−1 . Work done to increase the radius of soap bubble from 3.5 cm to 7 cm will be : [Take π=227 ]

The semicircles below have a radius of 21 cm each. Taking π as 227, what is the total area?

The surface area of a solid cylinder of radius 2.0 cm and height 10.0 cm is equal to ...... (mm)2

A solid cylindrical metallic rod 15-cm long with a diameter equal to 3.5 cm is melted intoanother rod of radius 3.5 cm. What will be the length of the new rod?

What voltage 4.5 cm away from the center of a metal sphere of radius 3.5 cm would produce a static charge of 2.2 μC?

1/3