Knowee
Questions
Features
Study Tools

Surface tension of a soap bubble is 2.0×10−2 N m−1 . Work done to increase the radius of soap bubble from 3.5 cm to 7 cm will be : [Take π=227 ]

Question

Surface tension of a soap bubble is 2.0×10−2 N m−1 .

Work done to increase the radius of soap bubble from 3.5 cm to 7 cm will be :
[Take π=227 \pi=227 ]

🧐 Not the exact question you are looking for?Go ask a question

Solution

The work done to increase the radius of a soap bubble can be calculated using the formula for the work done on a bubble, which is:

W = 8πr₁r₂σ

where:

  • W is the work done,
  • r₁ and r₂ are the initial and final radii of the bubble,
  • σ is the surface tension.

Given:

  • σ = 2.0×10−2 N m−1,
  • r₁ = 3.5 cm = 0.035 m (converted from cm to m),
  • r₂ = 7 cm = 0.07 m (converted from cm to m),
  • π = 22/7.

Substituting these values into the formula, we get:

W = 8 * (22/7) * 0.035 m * 0.07 m * 2.0×10−2 N m−1

Solving this, we get:

W = 0.024 Nm

So, the work done to increase the radius of the soap bubble from 3.5 cm to 7 cm is 0.024 Nm.

This problem has been solved

Similar Questions

When two soap bubbles of radii a and b (b > a) coalesce, the radius of curvature of common surface is:

The surface tension of water is 0.0730 N/m. What is the height of the water in a capillary tube of diameter 1.00 mm?

The surface tension of water is 0.0730 N/m. What is the height of the water in a capillary tube of diameter 2.00 mm?

A 7-ounce bottle of soap costs $6.14. What is the unit price, rounded to the nearest cent?

Take 5mL of the temporary hard water and add 2mL of soap solution. Shake vigorously.What is the result?

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.