The solubility of ionic compounds in water is determined by the balance between the energy required to break the ionic bonds in the solid and the energy released when the ions interact with water molecules.

1. PbI2 (Lead(II) iodide): This compound is slightly soluble in water. The solubility of PbI2 in water is low due to the high lattice energy of the compound, which is not sufficiently compensated by the hydration energy of the ions.

2. Pb3(PO4)2 (Lead(II) phosphate): This compound is insoluble in water. The phosphate ion (PO4^3-) forms insoluble salts with many cations, including Pb^2+.

3. Mg(OH)2 (Magnesium hydroxide): This compound is slightly soluble in water. The solubility of Mg(OH)2 in water is low due to the high lattice energy of the compound, which is not sufficiently compensated by the hydration energy of the ions.

4. MgI2 (Magnesium iodide): This compound is soluble in water. The iodide ion (I-) forms soluble salts with many cations, including Mg^2+. The hydration energy of the ions is sufficient to overcome the lattice energy of the compound, leading to its dissolution in water.

So, out of the given options, only MgI2 is expected to be soluble in water.

Question

The solubility of ionic compounds in water is determined by the balance between the energy required to break the ionic bonds in the solid and the energy released when the ions interact with water molecules.

1. PbI2 (Lead(II) iodide): This compound is slightly soluble in water. The solubility of PbI2 in water is low due to the high lattice energy of the compound, which is not sufficiently compensated by the hydration energy of the ions.

2. Pb3(PO4)2 (Lead(II) phosphate): This compound is insoluble in water. The phosphate ion (PO4^3-) forms insoluble salts with many cations, including Pb^2+.

3. Mg(OH)2 (Magnesium hydroxide): This compound is slightly soluble in water. The solubility of Mg(OH)2 in water is low due to the high lattice energy of the compound, which is not sufficiently compensated by the hydration energy of the ions.

4. MgI2 (Magnesium iodide): This compound is soluble in water. The iodide ion (I-) forms soluble salts with many cations, including Mg^2+. The hydration energy of the ions is sufficient to overcome the lattice energy of the compound, leading to its dissolution in water.

So, out of the given options, only MgI2 is expected to be soluble in water.

Knowee AI · Accepted Answer

The solubility of ionic compounds in water is determined by the balance between the energy required to break the ionic bonds in the solid and the energy released when the ions interact with water molecules.

1. PbI2 (Lead(II) iodide): This compound is slightly soluble in water. The solubility of PbI2 in water is low due to the high lattice energy of the compound, which is not sufficiently compensated by the hydration energy of the ions.

2. Pb3(PO4)2 (Lead(II) phosphate): This compound is insoluble in water. The phosphate ion (PO4^3-) forms insoluble salts with many cations, including Pb^2+.

3. Mg(OH)2 (Magnesium hydroxide): This compound is slightly soluble in water. The solubility of Mg(OH)2 in water is low due to the high lattice energy of the compound, which is not sufficiently compensated by the hydration energy of the ions.

4. MgI2 (Magnesium iodide): This compound is soluble in water. The iodide ion (I-) forms soluble salts with many cations, including Mg^2+. The hydration energy of the ions is sufficient to overcome the lattice energy of the compound, leading to its dissolution in water.

So, out of the given options, only MgI2 is expected to be soluble in water.

Which of the following ionic compounds are expected to be soluble in water?Group of answer choicesPbI2Pb3(PO4)2Mg(OH)2MgI2

Question

Which of the following ionic compounds are expected to be soluble in water?

Solution

Similar Questions

Upgrade your grade with Knowee