for the equation: (y + 5)2 = -12(x - 2); identify directrixQuestion 5Select one:x = 5y = -5y = 5x = 2Clear my choice◄ weekend sheet t3 w8Jump to...

The given equation is in the form of a parabola equation (y-k)^2 = 4a(x-h), where (h,k) is the vertex of the parabola, and 'a' is the distance from the vertex to the focus and the directrix.

The equation can be rewritten as (y + 5)^2 = -12(x - 2).

Here, the 'a' value is -3 (since 4a = -12), and the vertex (h,k) is (2,-5).

Since the 'a' value is negative, the parabola opens to the left.

The directrix of a parabola is a line that is a distance 'a' units from the vertex, and is perpendicular to the axis of symmetry.

For a parabola that opens to the left or right, the directrix is a vertical line (of the form x = constant).

Since the parabola opens to the left and the vertex is at x = 2, the directrix is a distance 'a' units to the right of the vertex, which is at x = 2 + (-3) = -1.

So, the directrix is x = -1.

However, this option is not given in your choices. Please check the equation or the choices again.