What is the magnitude of the Poynting vector, S = 4i - 3j + 2k?*1 point5.02 W/m^25.39 W/m^26.29 W/m^2D. 6.92 W/m^2
Question
What is the magnitude of the Poynting vector, S = 4i - 3j + 2k?
*1 point
5.02 W/m²
5.39 W/m²
6.29 W/m²
D. 6.92 W/m²
Solution
The magnitude of a vector is calculated using the formula:
|S| = sqrt((S_x)^2 + (S_y)^2 + (S_z)^2)
where S_x, S_y, and S_z are the components of the vector S.
In this case, S_x = 4, S_y = -3, and S_z = 2.
So, the magnitude of the Poynting vector S is:
|S| = sqrt((4)^2 + (-3)^2 + (2)^2) |S| = sqrt(16 + 9 + 4) |S| = sqrt(29)
Therefore, the magnitude of the Poynting vector S is approximately 5.39 W/m^2.
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