The given sequence of reactions involves three steps.

1. The first step is the reaction of phenol (C6H5OH) with sodium hydroxide (NaOH). This reaction will result in the formation of sodium phenoxide (C6H5ONa) and water (H2O).

2. The second step is the reaction of sodium phenoxide (C6H5ONa) with carbon dioxide (CO2). This reaction is known as the Kolbe-Schmitt reaction or carboxylation reaction, which will result in the formation of sodium salicylate (C6H4(OH)COONa).

3. The third step is the reaction of sodium salicylate (C6H4(OH)COONa) with hydrochloric acid (HCl). This reaction will result in the formation of salicylic acid (C6H4(OH)COOH) and sodium chloride (NaCl).

So, the compound (C) in the given sequence of reactions is salicylic acid (C6H4(OH)COOH).

Question

The given sequence of reactions involves three steps.

1. The first step is the reaction of phenol (C6H5OH) with sodium hydroxide (NaOH). This reaction will result in the formation of sodium phenoxide (C6H5ONa) and water (H2O).

2. The second step is the reaction of sodium phenoxide (C6H5ONa) with carbon dioxide (CO2). This reaction is known as the Kolbe-Schmitt reaction or carboxylation reaction, which will result in the formation of sodium salicylate (C6H4(OH)COONa).

3. The third step is the reaction of sodium salicylate (C6H4(OH)COONa) with hydrochloric acid (HCl). This reaction will result in the formation of salicylic acid (C6H4(OH)COOH) and sodium chloride (NaCl).

So, the compound (C) in the given sequence of reactions is salicylic acid (C6H4(OH)COOH).

Knowee AI · Accepted Answer

The given sequence of reactions involves three steps.

1. The first step is the reaction of phenol (C6H5OH) with sodium hydroxide (NaOH). This reaction will result in the formation of sodium phenoxide (C6H5ONa) and water (H2O).

2. The second step is the reaction of sodium phenoxide (C6H5ONa) with carbon dioxide (CO2). This reaction is known as the Kolbe-Schmitt reaction or carboxylation reaction, which will result in the formation of sodium salicylate (C6H4(OH)COONa).

3. The third step is the reaction of sodium salicylate (C6H4(OH)COONa) with hydrochloric acid (HCl). This reaction will result in the formation of salicylic acid (C6H4(OH)COOH) and sodium chloride (NaCl).

So, the compound (C) in the given sequence of reactions is salicylic acid (C6H4(OH)COOH).

The compound (C) in the given sequence of reaction is , C6H5OH−→−NaOH(A)−→CO2(B)−→HCl(C)

Question

The compound (C) in the given sequence of reaction is

Solution

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