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∠A, ∠B, ∠C are three angles of a triangle. If ∠A -∠B =18°, ∠B – ∠C = 45°, then, ∠B, ∠A and ∠C areChoices:-

Question

∠A, ∠B, ∠C are three angles of a triangle. If AB=18° ∠A - ∠B = 18° , BC=45° ∠B – ∠C = 45° , then, B,A ∠B, ∠A and C ∠C are

Choices:-

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Solution

1. Break Down the Problem

We know that the sum of the angles in a triangle is 180°. We have two relations:

  • AB=18 \angle A - \angle B = 18^\circ (1)
  • BC=45 \angle B - \angle C = 45^\circ (2)

We can express A \angle A and C \angle C in terms of B \angle B .

2. Relevant Concepts

Using the relations above:

  • From (1), we can express A \angle A as: A=B+18 \angle A = \angle B + 18^\circ

  • From (2), we find C \angle C as: C=B45 \angle C = \angle B - 45^\circ

3. Analysis and Detail

Now, substituting A \angle A and C \angle C in terms of B \angle B into the triangle angle sum equation:

A+B+C=180 \angle A + \angle B + \angle C = 180^\circ

Substituting the expressions for A \angle A and C \angle C : (B+18)+B+(B45)=180 (\angle B + 18^\circ) + \angle B + (\angle B - 45^\circ) = 180^\circ

This simplifies to: 3B27=180 3\angle B - 27^\circ = 180^\circ

Adding 27 27^\circ to both sides: 3B=207 3\angle B = 207^\circ

Dividing by 3: B=69 \angle B = 69^\circ

Now substituting back to find A \angle A and C \angle C : A=69+18=87 \angle A = 69^\circ + 18^\circ = 87^\circ C=6945=24 \angle C = 69^\circ - 45^\circ = 24^\circ

4. Verify and Summarize

Now we verify the angles:

  • A=87 \angle A = 87^\circ
  • B=69 \angle B = 69^\circ
  • C=24 \angle C = 24^\circ

Checking the sum: 87+69+24=180 87^\circ + 69^\circ + 24^\circ = 180^\circ

This is correct.

Final Answer

  • A=87 \angle A = 87^\circ
  • B=69 \angle B = 69^\circ
  • C=24 \angle C = 24^\circ

This problem has been solved

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