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16. Calculate the time it takes a 0.5 kW appliance to transfer 1.3 kJ of energy (1dp)

Question

16. Calculate the time it takes a 0.5 kW appliance to transfer 1.3 kJ of energy (1dp)

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Solution

Sure, here's how you can calculate it:

Step 1: First, we need to convert the power of the appliance from kilowatts (kW) to joules per second (J/s) because the energy is given in joules (J). We know that 1 kW = 1000 J/s. So, 0.5 kW = 0.5 * 1000 = 500 J/s.

Step 2: Next, we need to convert the energy from kilojoules (kJ) to joules (J). We know that 1 kJ = 1000 J. So, 1.3 kJ = 1.3 * 1000 = 1300 J.

Step 3: Now, we can calculate the time it takes for the appliance to transfer this energy. We know that power = energy / time. So, rearranging for time, we get time = energy / power = 1300 J / 500 J/s = 2.6 seconds.

So, it takes approximately 2.6 seconds for a 0.5 kW appliance to transfer 1.3 kJ of energy.

This problem has been solved

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