What happens when you try to solve the pair of simultaneous equations y equals 2x - 15 and y equals x square - 3x - 4

To solve the pair of simultaneous equations y = 2x - 15 and y = x^2 - 3x - 4, you can use the method of substitution or elimination. Here, we will use substitution since y is already isolated in both equations.

Step 1: Set the two equations equal to each other because they both equal y.

2x - 15 = x^2 - 3x - 4

Step 2: Rearrange the equation to set it equal to zero.

0 = x^2 - 5x + 11

Step 3: Solve for x using the quadratic formula x = [-b ± sqrt(b^2 - 4ac)] / 2a.

Here, a = 1, b = -5, and c = 11.

x = [5 ± sqrt((-5)^2 - 4111)] / 2*1 x = [5 ± sqrt(25 - 44)] / 2 x = [5 ± sqrt(-19)] / 2

Since the term under the square root is negative, there are no real solutions for x.

Step 4: Since there are no real solutions for x, there are also no real solutions for y.

Therefore, the given pair of simultaneous equations has no real solutions.