How many grams of Ca2+ in 81.59 g of limestone (CaCO3)? Answer to 2 decimal pointsMW (Ca) = 40.08 g.mol-1MW (CaCO3) = 100.09 g.mol-1
Question
Solution 1
The number of grams of a component in a compound can be calculated using the formula:
Grams of component = (mass of compound / molar mass of compound) * molar mass of component
Given: Mass of CaCO3 (limestone) = 81.59 g Molar mass of CaCO3 = 100.09 g/mol Molar mass of Ca = 40.08 g/mol
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