A  3L water sample has a hardness of 300ppm by mass CaCO3. The grams of Calcium Carbonate CaCO3 is:Question 34Select one:a.1.0gb.0.20gc.0.30gd.1.20g

To find the grams of Calcium Carbonate (CaCO3) in the 3L water sample with a hardness of 300ppm by mass CaCO3, we can use the following steps:

Step 1: Convert the ppm (parts per million) to a mass ratio. Since 1 ppm is equivalent to 1 mg/L, we can convert 300 ppm to 300 mg/L.

Step 2: Convert the mg/L to grams. Since 1 L of water has a mass of 1000 grams, we can convert 300 mg/L to grams by dividing it by 1000. 300 mg/L = 0.3 g/L

Step 3: Multiply the grams per liter by the volume of the water sample. Since we have a 3L water sample, we can multiply 0.3 g/L by 3 to find the total grams of CaCO3. 0.3 g/L * 3 L = 0.9 g

Therefore, the grams of Calcium Carbonate (CaCO3) in the 3L water sample is 0.9g.

So, the correct answer is option c. 0.30g.