certain vinegar contains an acetic acid with a volume of 55 mL and water with 215 mL. What is the % by volume for the solvent?a.26%b.20%c.80%d.89%
Question
certain vinegar contains an acetic acid with a volume of 55 mL and water with 215 mL. What is the % by volume for the solvent?
a. 26%
b. 20%
c. 80%
d. 89%
Solution
The solvent in this case is water. To find the percentage by volume of the solvent, you need to divide the volume of the solvent by the total volume and then multiply by 100.
Here are the steps:
-
Add the volume of acetic acid and water to find the total volume: 55 mL (acetic acid) + 215 mL (water) = 270 mL (total volume).
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Divide the volume of the solvent (water) by the total volume: 215 mL (water) / 270 mL (total volume) = 0.7963.
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Multiply by 100 to get the percentage: 0.7963 * 100 = 79.63%.
So, the percentage by volume of the solvent (water) in the vinegar is approximately 80%. Therefore, the correct answer is c.80%.
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