The group velocity of a wave is given by the derivative of the dispersion relation with respect to the wave number k. In this case, the dispersion relation is ω(k) = C|sin(ka)|.

To find the group velocity, we need to take the derivative of ω with respect to k:

v_g = dω/dk = C * cos(ka) * a

The group velocity of the wave vanishes (i.e., becomes zero) when cos(ka) = 0. This occurs when ka = (2n+1)π/2, where n is an integer. Therefore, the group velocity of the wave vanishes at k = (2n+1)π/(2a), for n = 0, ±1, ±2, ....

Question

The group velocity of a wave is given by the derivative of the dispersion relation with respect to the wave number k. In this case, the dispersion relation is ω(k) = C|sin(ka)|.

To find the group velocity, we need to take the derivative of ω with respect to k:

v_g = dω/dk = C * cos(ka) * a

The group velocity of the wave vanishes (i.e., becomes zero) when cos(ka) = 0. This occurs when ka = (2n+1)π/2, where n is an integer. Therefore, the group velocity of the wave vanishes at k = (2n+1)π/(2a), for n = 0, ±1, ±2, ....

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The group velocity of a wave is given by the derivative of the dispersion relation with respect to the wave number k. In this case, the dispersion relation is ω(k) = C|sin(ka)|.

To find the group velocity, we need to take the derivative of ω with respect to k:

v_g = dω/dk = C * cos(ka) * a

The group velocity of the wave vanishes (i.e., becomes zero) when cos(ka) = 0. This occurs when ka = (2n+1)π/2, where n is an integer. Therefore, the group velocity of the wave vanishes at k = (2n+1)π/(2a), for n = 0, ±1, ±2, ....

ispersion relaxtation for a wave is given at omega(k)=C|sinka|,where C is a constant the group velocity of wave vanishes at

Question

Dispersion relaxation for a wave is given at $\omega(k) = C |\sin(k a)|$ , where $C$ is a constant. The group velocity of the wave vanishes at

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