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Find how many different 4-digit numbers can be formed using the digits 1. 2, 3, 4, 5 and 6 that are greater than 6000 are odd?

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Solution

Sure, here is the step by step solution:

  1. Since the number has to be greater than 6000, the thousands place can be filled by any of the 3 digits (6, 5, 4). So, there are 3 ways to fill the thousands place.

  2. The units place has to be an odd number. So, it can be filled by any of the 3 odd digits (1, 3, 5). So, there are 3 ways to fill the units place.

  3. The remaining 2 places (hundreds and tens) can be filled by any of the remaining 4 digits. So, there are 4 ways to fill the hundreds place and 3 ways to fill the tens place.

  4. Therefore, the total number of 4-digit numbers that can be formed is 3 (for thousands place) * 3 (for units place) * 4 (for hundreds place) * 3 (for tens place) = 108.

This problem has been solved

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