The output of the code will be ____. int i=5; printf(“%d %d %d”, i, i++, ++i); ans. 5 5 7 7 6 6 7 6 5 7 6 7
Question
The output of the code will be ____.
int i=5;
printf("%d %d %d", i, i++, ++i);
ans.
- 5 5 7
- 7 6 6
- 7 6 5
- 7 6 7
Solution
To determine the output of the provided code, we need to analyze how the variables are evaluated in the printf statement. The key here is to understand how the post-increment (i++) and pre-increment (++i) operators work.
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Variable Initialization:
int i = 5;
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Function Call:
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