A body covered a distance of 5 m along a semicircular path. The ratio of distance to displacement is
Question
A body covered a distance of 5 m along a semicircular path. The ratio of distance to displacement is
Solution
The distance covered by the body is 5 m along a semicircular path.
The displacement of the body is the straight line distance from the initial to the final position. In a semicircular path, the displacement is equal to the diameter of the semicircle.
The diameter of a semicircle is twice the radius. We know that the circumference of a full circle is 2πr. Therefore, the length of a semicircle is πr. If this length is 5 m, then the radius r is 5/π.
Therefore, the diameter (which is the displacement in this case) is 2r = 2*(5/π) = 10/π.
The ratio of distance to displacement is therefore 5/(10/π) = π/2.
Similar Questions
A body covered a distance of z metre along a semicircular path. Calculate the magnitude ofdisplacement of the body, and the ratio of distance to displacement?
A particle is moving in a circle of diameter 5m. What is its displacement when it covers oneand a half revolution?
A body is moving along a circular path of radius R. what will be the distanceand displacement of the body when it completes half a revolution?
A body rises vertically upward to a height of 100 m, in 5 seconds, then comes back to the same position after another 5 s. Find the displacement of the body.
A body rises vertically upward to a height of 100 m, in 5 seconds, then comes back to the same position after another 5 s. Find the distance travelled in m.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.