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Classify the following partial differential equations:(i) ๐œ•2๐‘ข๐œ•๐‘ฅ2 + 3 ๐œ•2๐‘ข๐œ•๐‘ฆ2 = ๐œ•๐‘ข

Question

Classify the following partial differential equations:

(i) โˆ‚2uโˆ‚x2+3โˆ‚2uโˆ‚y2=โˆ‚uโˆ‚t \frac{\partial^2 u}{\partial x^2} + 3 \frac{\partial^2 u}{\partial y^2} = \frac{\partial u}{\partial t}

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Solution

The given partial differential equation is:

๐œ•ยฒ๐‘ข/๐œ•๐‘ฅยฒ + 3 ๐œ•ยฒ๐‘ข/๐œ•๐‘ฆยฒ = ๐œ•๐‘ข

To classify this PDE, we need to look at the highest order derivatives. In this case, we have second order derivatives with respect to x and y.

The general form of a second order PDE is:

A(๐œ•ยฒ๐‘ข/๐œ•๐‘ฅยฒ) + B(๐œ•ยฒ๐‘ข/๐œ•๐‘ฆยฒ) + C(๐œ•๐‘ข/๐œ•๐‘ฅ) + D(๐œ•๐‘ข/๐œ•๐‘ฆ) + E๐‘ข = F

Where A, B, C, D, E are coefficients which can be functions of x and y.

The classification of the PDE depends on the discriminant Bยฒ - 4AC.

In our case, A = 1, B = 3, C = 0, D = 0, E = 0. So, the discriminant is Bยฒ - 4AC = 3ยฒ - 410 = 9.

Since the discriminant is positive, the given PDE is an elliptic type.

This problem has been solved

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