XeF6 + H2O  →       A + B                                     Compound A & B are respectively;XeO4, HFXeO3, HFXeF2, XeMore than one of the above

To analyze the reaction between xenon hexafluoride (XeF₆) and water (H₂O), we need to consider the possible products formed when these substances interact. Let’s break down the process:

Step 1: Understand the Reactants

• Xenon Hexafluoride (XeF₆) is a strong fluorinating agent.
• Water (H₂O) is a common solvent and can act as a nucleophile in many chemical reactions.

Step 2: Predict the Products

When XeF₆ reacts with water, hydrolysis may occur, leading to the formation of various xenon oxo-fluoride compounds as products. The reactions typically yield xenon oxides and hydrogen fluoride (HF) as a byproduct.

Step 3: Possible Products

The possible products indicated in the question are:

1. XeO₄ (Xenon tetroxide)
2. HF (Hydrofluoric acid)
3. XeO₃ (Xenon trioxide)
4. HF (again, which is already mentioned)
5. XeF₂ (Xenon difluoride)
6. More than one of the above.

Step 4: Analyzing Each Compound

1. XeO₄ is generated under certain conditions when XeF₆ reacts with an excess of water.
2. XeO₃ can also be formed, depending on the stoichiometry of water used.
3. HF is a byproduct due to the release of fluoride ions reacting with water.
4. XeF₂ could potentially be produced from the reaction if less water is used.

Step 5: Conclusion

Considering these possibilities and based on typical hydrolysis reactions of halides, compounds A and B in the reaction could be both XeO₄ and HF if enough water is present. Therefore, the most appropriate answer among the options provided is:

Final Answer

More than one of the above (specifically, XeO₄ and HF).