The equation of the projectile is  y=20x−54x2 m.𝑦=20𝑥-54𝑥2 m. The horizontal range is

The horizontal range of a projectile can be found using the equation of the projectile's trajectory. The equation given is y = 20x - 54x^2.

The horizontal range, R, is the x-coordinate where the projectile hits the ground, i.e., when y = 0.

So, we set y = 0 in the equation and solve for x:

0 = 20x - 54x^2 0 = x(20 - 54x)

Setting each factor equal to zero gives the solutions:

x = 0 or 20 - 54x = 0

The first solution, x = 0, corresponds to the starting point of the projectile. The second solution gives the horizontal range:

20 - 54x = 0 54x = 20 x = 20/54 x = 0.37 m

So, the horizontal range of the projectile is 0.37 meters.