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What is the empirical formula of the conjugate acid of the anion in strontium acetate, Sr(CH3COO)2?A.CH2OB.C2H4O2C.SrC2H3O2D.NaC2H3O2

Question

What is the empirical formula of the conjugate acid of the anion in strontium acetate, Sr(CH3COO)2?

A. CH2O
B. C2H4O2
C. SrC2H3O2
D. NaC2H3O2

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Solution

The conjugate acid of the anion in strontium acetate, Sr(CH3COO)2, is formed by adding a proton (H+) to the anion. The anion in strontium acetate is the acetate ion, CH3COO-.

Step 1: Identify the anion in the compound. In Sr(CH3COO)2, the anion is CH3COO- (acetate ion).

Step 2: Form the conjugate acid by adding a proton (H+) to the anion. When we add a proton to the acetate ion, we get CH3COOH.

So, the empirical formula of the conjugate acid of the anion in strontium acetate is CH3COOH, which simplifies to C2H4O2.

Therefore, the correct answer is B. C2H4O2.

This problem has been solved

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