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Fill in the missing chemical formulae in the tables below.acid conjugate base base conjugate acidHCO−3 H2PO−4 HCl I− H2O SO2−4

Question

Fill in the missing chemical formulae in the tables below.

acid conjugate base base conjugate acid
HCO−3 H2PO−4 HCl
I− H2O SO2−4
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Solution

To fill in the missing chemical formulae, we will denote the following:

  1. Acids are proton donors, and their conjugate bases are formed by losing a proton (H⁺).
  2. Bases are proton acceptors, and their conjugate acids are formed by gaining a proton (H⁺).

Step 1: Identify the missing conjugate base for HCO₃⁻

  • HCO₃⁻ (bicarbonate) can lose a proton to form its conjugate base.
  • Thus, HCO₃⁻ → H⁺ + CO₃²⁻.
  • The conjugate base of HCO₃⁻ is CO₃²⁻.

Step 2: Identify the missing conjugate acid for H₂PO₄⁻

  • H₂PO₄⁻ (dihydrogen phosphate) can accept a proton to form its conjugate acid.
  • Thus, H₂PO₄⁻ + H⁺ → H₃PO₄.
  • The conjugate acid is H₃PO₄.

Step 3: Identify the missing conjugate base for HCl

  • HCl (hydrochloric acid) can lose a proton to form its conjugate base.
  • Thus, HCl → H⁺ + Cl⁻.
  • The conjugate base is Cl⁻ (not I⁻).

Step 4: Identify the missing conjugate acid for H₂O

  • H₂O (water) can accept a proton to form its conjugate acid.
  • Thus, H₂O + H⁺ → H₃O⁺.
  • The conjugate acid is H₃O⁺.

Step 5: Identify the missing conjugate base for SO₄²⁻

  • SO₄²⁻ (sulfate) can lose a proton to form its conjugate base.
  • Thus, SO₄²⁻ → H⁺ + HSO₄⁻.
  • The conjugate base is HSO₄⁻.

Summary of Findings

Now we can compile the findings into the table format.

Acid Conjugate Base Base Conjugate Acid
HCO₃⁻ CO₃²⁻ H₂PO₄⁻ H₃PO₄
HCl Cl⁻ I⁻ H₂O
H₂O HSO₄⁻ SO₄²⁻ H₃O⁺

Putting the information clearly into the table:

Acid Conjugate Base Base Conjugate Acid
HCO₃⁻ CO₃²⁻ H₂PO₄⁻ H₃PO₄
HCl Cl⁻ I⁻ H₃O⁺
H₂O HSO₄⁻ SO₄²⁻ H₃O⁺

Final Answer

The completed table of chemical formulae is shown above.

This problem has been solved

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