A body is thrown up with a velocity 40m𝑠-1. At same time another body is dropped from a height 40 m. Their relative acceleration after 1.3 seconds is
Question
A body is thrown up with a velocity 40 m/s. At the same time, another body is dropped from a height 40 m. Their relative acceleration after 1.3 seconds is
Solution
The relative acceleration between two bodies is the difference in their individual accelerations.
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The first body is thrown upwards with an initial velocity. However, regardless of its initial velocity, a body moving under the influence of gravity alone (in the absence of other forces like air resistance) always has a constant acceleration equal to the acceleration due to gravity. This is directed downwards and has a magnitude of approximately 9.8 m/s².
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The second body is dropped from a height. This means it is also moving under the influence of gravity alone, so it also has a constant acceleration of 9.8 m/s² downwards.
Therefore, the acceleration of both bodies is the same (9.8 m/s² downwards), so their relative acceleration is 0.
In other words, each body 'sees' the other as moving with a constant velocity, not accelerating.
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