The velocity changes from 45m/s to 60m/s in Three seconds. What is its acceleration?

1. Break Down the Problem

To find the acceleration, we need to determine the change in velocity and the time over which this change occurs.

1. Initial velocity (u) = 45 m/s
2. Final velocity (v) = 60 m/s
3. Time (t) = 3 seconds

2. Relevant Concepts

Acceleration ($a$) can be calculated using the formula:

$a = \frac{v - u}{t}$

where:

• $v$ is the final velocity,
• $u$ is the initial velocity,
• $t$ is the time taken for the change in velocity.

3. Analysis and Detail

Substituting the known values into the formula:

$a = \frac{60 \, \text{m/s} - 45 \, \text{m/s}}{3 \, \text{s}} = \frac{15 \, \text{m/s}}{3 \, \text{s}} = 5 \, \text{m/s}^2$

4. Verify and Summarize

The calculations have been verified as follows:

1. Change in velocity = $60 \, \text{m/s} - 45 \, \text{m/s} = 15 \, \text{m/s}$
2. Time = 3 seconds
3. Acceleration = $\frac{15 \, \text{m/s}}{3 \, \text{s}} = 5 \, \text{m/s}^2$

Thus, the acceleration is correctly calculated.

Final Answer

The acceleration is $5 \, \text{m/s}^2$.