How long does it take a falling object (dropped from rest) to reach a downward velocity of 113 m/s?

To solve this problem, we can use the formula of motion which states that final velocity (v) equals initial velocity (u) plus acceleration (a) times time (t). In this case, the object is dropped from rest, so the initial velocity is 0. The acceleration is due to gravity, which is approximately 9.8 m/s² on Earth. The final velocity is given as 113 m/s. So, we can set up the equation as follows:

113 m/s = 0 + 9.8 m/s² * t

To solve for time (t), we can rearrange the equation:

t = 113 m/s / 9.8 m/s²

Now, we just need to do the division to find the time:

t ≈ 11.53 seconds

So, it would take approximately 11.53 seconds for a falling object to reach a downward velocity of 113 m/s when dropped from rest on Earth.