Given that Z is a standard normal random variable, P(Z > − 2.68) is:Group of answer choices0.4963.0.5037.0.9963.0.0037.
Question
Solution 1
The value of P(Z > -2.68) is 0.9963.
Here's why:
The standard normal distribution table provides the probability that a normally distributed random variable Z, with mean equal to 0 and variance equal to 1, is less than or equal to z.
P(Z > -2.68) is the same as 1 - P(Z ≤ -2.68).
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