The reaction A + 2B + C → D + 2E is first order in reactant A, first order in B, and second order in C. What is the rate law equation for this reaction?
Question
The reaction
is first order in reactant A, first order in B, and second order in C.
What is the rate law equation for this reaction?
Solution
The rate law for a chemical reaction is an equation that links the reaction rate with the concentrations of the reactants. Each reactant concentration is raised to a power equal to the order of that reactant in the reaction.
Given the reaction A + 2B + C → D + 2E, which is first order in reactant A, first order in B, and second order in C, the rate law equation would be:
Rate = k[A][B][C]^2
Here, [A], [B], and [C] represent the molar concentrations of the reactants A, B, and C, respectively. The term 'k' is the rate constant for the reaction. The powers to which the concentrations are raised correspond to the order of the reaction with respect to each reactant.
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