Calculate the energy required to increase the temperature of 0.60 kg of water from 31°C to 56°C.
Question
Calculate the energy required to increase the temperature of 0.60 kg of water from 31°C to 56°C.
Solution
To calculate the energy required to heat the water, we can use the formula for heat energy:
Q = mcΔT
where:
- Q is the heat energy (in joules)
- m is the mass of the substance (in kilograms)
- c is the specific heat capacity (for water, it's approximately 4186 J/kg°C)
- ΔT is the change in temperature (in degrees Celsius)
Given:
- m = 0.60 kg
- c = 4186 J/kg°C
- ΔT = 56°C - 31°C = 25°C
Substitute these values into the formula:
Q = (0.60 kg) * (4186 J/kg°C) * (25°C) = 62790 J
So, the energy required to increase the temperature of 0.60 kg of water from 31°C to 56°C is 62790 Joules.
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