The complex compound [Cu(NH3)4][PtCl4] has two parts: the cation [Cu(NH3)4]2+ and the anion [PtCl4]2-.

1. For the cation [Cu(NH3)4]2+:
The copper ion is coordinated to four ammonia molecules. As all the ligands are identical, there is only one possible arrangement, so there is only one isomer.

2. For the anion [PtCl4]2-:
The platinum ion is coordinated to four chloride ions. Again, as all the ligands are identical, there is only one possible arrangement, so there is only one isomer.

Therefore, the total number of possible isomers for the complex compound [Cu(NH3)4][PtCl4] is 1 (from the cation) x 1 (from the anion) = 1.

Question

The complex compound [Cu(NH3)4][PtCl4] has two parts: the cation [Cu(NH3)4]2+ and the anion [PtCl4]2-.

1. For the cation [Cu(NH3)4]2+: 
   The copper ion is coordinated to four ammonia molecules. As all the ligands are identical, there is only one possible arrangement, so there is only one isomer.

2. For the anion [PtCl4]2-: 
   The platinum ion is coordinated to four chloride ions. Again, as all the ligands are identical, there is only one possible arrangement, so there is only one isomer.

Therefore, the total number of possible isomers for the complex compound [Cu(NH3)4][PtCl4] is 1 (from the cation) x 1 (from the anion) = 1.

Knowee AI · Accepted Answer

The complex compound [Cu(NH3)4][PtCl4] has two parts: the cation [Cu(NH3)4]2+ and the anion [PtCl4]2-.

1. For the cation [Cu(NH3)4]2+: 
   The copper ion is coordinated to four ammonia molecules. As all the ligands are identical, there is only one possible arrangement, so there is only one isomer.

2. For the anion [PtCl4]2-: 
   The platinum ion is coordinated to four chloride ions. Again, as all the ligands are identical, there is only one possible arrangement, so there is only one isomer.

Therefore, the total number of possible isomers for the complex compound [Cu(NH3)4][PtCl4] is 1 (from the cation) x 1 (from the anion) = 1.

The total number of possible isomers for the complex compound [Cu(NH3)4][PtCl4]

Question

The total number of possible isomers for the complex compound [Cu(NH₃)₄][PtCl₄]

Solution

Similar Questions

Upgrade your grade with Knowee