The mass defect for the nucleus of helium is 0.0303 amu. What is the binding energy per nucleon for helium in MeV :-28741
Question
The mass defect for the nucleus of helium is 0.0303 amu. What is the binding energy per nucleon for helium in MeV?**
Answer: -28741
Solution
The mass defect of an atom is the difference between the mass of an unbound system of protons and neutrons and the mass of the bound nucleus. It is often expressed in energy units (electron volts) through Einstein's equation E=mc^2.
The mass defect for the helium nucleus is given as 0.0303 atomic mass units (amu).
1 amu is approximately equal to 931.5 MeV (mega electron volts).
So, the total binding energy for the helium nucleus is 0.0303 amu * 931.5 MeV/amu = 28.21 MeV.
A helium nucleus contains 4 nucleons (2 protons and 2 neutrons).
Therefore, the binding energy per nucleon for helium is 28.21 MeV / 4 = 7.05 MeV/nucleon.
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