Knowee
Questions
Features
Study Tools

The mass defect for the nucleus of helium is 0.0303 amu. What is the binding energy per nucleon for helium in MeV :-28741

Question

The mass defect for the nucleus of helium is 0.0303 amu. What is the binding energy per nucleon for helium in MeV?**

Answer: -28741

🧐 Not the exact question you are looking for?Go ask a question

Solution

The mass defect of an atom is the difference between the mass of an unbound system of protons and neutrons and the mass of the bound nucleus. It is often expressed in energy units (electron volts) through Einstein's equation E=mc^2.

The mass defect for the helium nucleus is given as 0.0303 atomic mass units (amu).

1 amu is approximately equal to 931.5 MeV (mega electron volts).

So, the total binding energy for the helium nucleus is 0.0303 amu * 931.5 MeV/amu = 28.21 MeV.

A helium nucleus contains 4 nucleons (2 protons and 2 neutrons).

Therefore, the binding energy per nucleon for helium is 28.21 MeV / 4 = 7.05 MeV/nucleon.

This problem has been solved

Similar Questions

What is the binding energy of a nucleus that has a mass defect of 5.81 𝑥x 10-29 kg?A.5.23 𝑥x 10-12 JB.1.57 𝑥x 10-3 JC.9.44 𝑥x 1020 JD.3.15 𝑥x 1012 J

If the binding energy per nucleon in Li7 and He4 nuclei are 5.60 MeV and 7.06 MeV , then what is the energy of the reaction 3Li7 + 1H1 = 2 2He4 ?

calculate the binding energy of 1 mole of C-14 nuclei. The experimentally determined mass of carbon-14 atom (including its 6 electrons) is 14.00342 u

The binding energies of the nuclei of He, Li, C &  N are 28, 52, 90, 98 MeV respectively. Which of these is most stable. He  Li C N

Which of the following has mass of 1 amu?Select answersAProtonBNeutronCHydrogen atomD α -particle

1/2

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.