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If the binding energy per nucleon in Li7 and He4 nuclei are 5.60 MeV and 7.06 MeV , then what is the energy of the reaction 3Li7 + 1H1 = 2 2He4 ?

Question

If the binding energy per nucleon in Li7 and He4 nuclei are 5.60 MeV and 7.06 MeV , then what is the energy of the reaction 3Li7 + 1H1 = 2 2He4 ?
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Solution 1

To solve this problem, we need to calculate the total binding energy before and after the reaction and then find the difference.

Step 1: Calculate the total binding energy before the reaction. The total binding energy before the reaction is the sum of the binding energy of 3 Li7 nuclei and 1 H1 nuc Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.

Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
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