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At which temperature would a reaction with H = -92 kJ/mol, S = -0.199 kJ/(molK) be spontaneous?A.400 KB.500 KC.600 KD.700 KSUBMITarrow_backPREVIOUS

Question

At which temperature would a reaction with H = -92 kJ/mol, S = -0.199 kJ/(molK) be spontaneous?A.400 KB.500 KC.600 KD.700 KSUBMITarrow_backPREVIOUS
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Solution 1

The spontaneity of a reaction can be determined using the Gibbs Free Energy equation:

ΔG = ΔH - TΔS

Where: ΔG is the change in Gibbs Free Energy ΔH is the change in enthalpy T is the temperature in Kelvin ΔS is the change in entropy

For a reaction to be spontaneous, ΔG must be less than 0.

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