At what temperature (in K) does the following reaction become spontaneous, if Δ𝐻∘ = 311.1 kJ/mol and Δ𝑆∘ = 707.3 J/mol*K?

Question

At what temperature (in K) does the following reaction become spontaneous, if Δ𝐻∘ = 311.1 kJ/mol and Δ𝑆∘ = 707.3 J/mol*K?
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Solution 1

The reaction becomes spontaneous when ΔG° < 0. The formula for ΔG° is ΔG° = ΔH° - TΔS°.

To find the temperature at which the reaction becomes spontaneous, we set ΔG° = 0 and solve for T:

0 = ΔH° - TΔS° T = ΔH° / ΔS°

Substituting the given values:

T = (311.1 kJ/mol) / (707.3 J/mol*K)

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