In dark reactions: 6CO2 + A + 12NADPH + H+ ⟶ C6H12O6 + 6H2O + B + 18H3PO4 + 12NADPA and B are respectively:
Question
In dark reactions:
A and B are respectively:
Solution
The equation you provided is for the dark reactions of photosynthesis, also known as the Calvin cycle. In this process, carbon dioxide (CO2) is converted into glucose (C6H12O6). The equation is usually written as:
6CO2 + 18ATP + 12NADPH + H+ → C6H12O6 + 6H2O + 18ADP + 18Pi + 12NADP+
Comparing this with your equation, we can see that:
A = 18ATP B = 18ADP + 18Pi
So, A and B are respectively 18ATP and 18ADP + 18Pi.
Similar Questions
In dark reactions: 6CO2 + A + 12NADPH + H+ ⟶ C6H12O6 + 6H2O + B + 18H3PO4 + 12NADPA and B are respectively:
What does the photosynthetic reaction of plants exhibit? [6CO2 + 6H2O + light → C6H12O6 + 6 O2] *EndothermicExothermicReversibleNone of these
Which of the following represents an aromatic compound?A. C6H5OHB. C6H12C. C6H9OHD. C6H8
What would be the major product of the following reaction?C6H5 -CH2-OC6H5 + HBr A + B
Which molecule is produced during the light reactions of photosynthesis?O2ADPCO2C6H12O6
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