AppOrchid conducted a test that had a mean score of 150 and a standard deviation of 20. If a candidate's z-score is 1.50, what was his score on the test?
Question
AppOrchid conducted a test that had a mean score of 150 and a standard deviation of 20. If a candidate's z-score is 1.50, what was his score on the test?
Solution
To find the candidate's score on the test, we can use the formula for z-score:
z = (x - μ) / σ
Where: z = z-score x = candidate's score μ = mean score σ = standard deviation
Given that the z-score is 1.50, the mean score is 150, and the standard deviation is 20, we can rearrange the formula to solve for x:
1.50 = (x - 150) / 20
To isolate x, we can multiply both sides of the equation by 20:
1.50 * 20 = x - 150
30 = x - 150
Next, we can add 150 to both sides of the equation:
30 + 150 = x
180 = x
Therefore, the candidate's score on the test is 180.
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