If 2.25 moles of LiF are added to water resulting in 125 mL of aqueous LiF, what is the molarity of the solution?
Question
If 2.25 moles of LiF are added to water resulting in 125 mL of aqueous LiF, what is the molarity of the solution?
Solution
To calculate the molarity of the solution, we need to use the formula:
Molarity (M) = moles of solute / liters of solution
Given in the problem, we have:
Moles of solute (LiF) = 2.25 moles Volume of solution = 125 mL
First, we need to convert the volume from milliliters to liters because the volume in the molarity formula is in liters.
1 liter = 1000 milliliters
So, 125 mL = 125 / 1000 = 0.125 liters
Now we can substitute these values into the molarity formula:
Molarity (M) = 2.25 moles / 0.125 liters = 18 M
So, the molarity of the solution is 18 M.
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