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What is the greatest number of acute angles that a triangle can contain?A.0B.3C.2D.1SUBMITarrow_backPREVIOUS

Question

What is the greatest number of acute angles that a triangle can contain?

A. 0
B. 3
C. 2
D. 1

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Solution

Break Down the Problem

  1. Identify the types of angles in a triangle: acute, right, and obtuse.
  2. Understand the relationship between the angles in a triangle, which must sum to 180180^\circ.

Relevant Concepts

  1. An acute angle is an angle less than 9090^\circ.
  2. A triangle can contain different types of angles, but the sum of all angles in a triangle adheres to the rule: Sum of angles=180 \text{Sum of angles} = 180^\circ

Analysis and Detail

  1. If a triangle were to contain three acute angles, then each angle AA, BB, and CC must satisfy: A<90,B<90,C<90 A < 90^\circ, \quad B < 90^\circ, \quad C < 90^\circ So, the maximum would be: A+B+C<270 A + B + C < 270^\circ This contradicts the triangle angle sum property. Therefore, having three acute angles is impossible.

  2. If a triangle contains one obtuse angle (greater than 9090^\circ), the remaining two angles must be acute to satisfy the triangle's angle sum: Obtuse Angle>90    Two Acute Angles<90 \text{Obtuse Angle} > 90^\circ \implies \text{Two Acute Angles} < 90^\circ Hence, it is possible to have two acute angles while having one obtuse angle.

  3. A triangle can also contain one right angle (equal to 9090^\circ), allowing the other two angles to also be acute: Right Angle=90    A+B<90 \text{Right Angle} = 90^\circ \implies A + B < 90^\circ So, two angles can still be acute if one angle is right.

Verify and Summarize

Evaluating these possibilities:

  • Three Acute Angles: Not possible (angle sum exceeds 180180^\circ).
  • Two Acute Angles: Possible with one obtuse angle.
  • One Acute Angle: Possible, but also more limiting than two acute angles.

Thus, the maximum number of acute angles in a triangle is two.

Final Answer

The greatest number of acute angles that a triangle can contain is 2 (C).

This problem has been solved

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