0.209 mol of Cr₂(SO₄)₃ is dissolved in water to produce a solution with a concentration of 2.28 M. What is the volume of this solution in liters?
Question
What is the volume of the solution produced by dissolving 0.209 mol of Cr₂(SO₄)₃ in water to achieve a concentration of 2.28 M?
Solution
To find the volume of the solution, we can use the formula for molarity which is:
Molarity (M) = moles of solute / volume of solution in liters
We know the molarity (2.28 M) and the moles of solute (0.209 mol), so we can rearrange the formula to solve for the volume of the solution:
Volume of solution in liters = moles of solute / Molarity
Substituting the given values:
Volume of solution in liters = 0.209 mol / 2.28 M = 0.0917 liters
So, the volume of the solution is approximately 0.0917 liters.
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