0.13 mol of TiCl4 is dissolved in water to produce a solution with a concentration of 2 M. What is the volume of this solution in liters?

1. Break Down the Problem

To find the volume of the solution, we need to use the relationship between moles, concentration, and volume. The formula that relates these is:

$\text{Concentration (M)} = \frac{\text{Number of moles (mol)}}{\text{Volume (L)}}$

2. Relevant Concepts

We rearrange the formula to solve for volume:

$\text{Volume (L)} = \frac{\text{Number of moles (mol)}}{\text{Concentration (M)}}$

3. Analysis and Detail

We know:

• The number of moles of TiCl4 = 0.13 mol
• The concentration of the solution = 2 M

Now, substituting the values into the rearranged formula:

$\text{Volume (L)} = \frac{0.13 \, \text{mol}}{2 \, \text{M}}$

4. Verify and Summarize

Calculating the volume:

$\text{Volume (L)} = \frac{0.13}{2} = 0.065 \, \text{L}$

Final Answer

The volume of the solution is $0.065 \, \text{L}$.