Calculate the number of fission in uranium per second required to produce 2 kW ofpower if energy released per fission is 200 meV

Sure, let's break this down step by step:

1. First, we need to convert the energy released per fission from meV to Joules, since the power we want to produce is in kW (which is a unit derived from Joules). 1 eV (electronvolt) is approximately 1.60218 x 10^-19 Joules. Therefore, 200 meV is 200 x 10^-3 eV, which is 200 x 10^-3 x 1.60218 x 10^-19 Joules = 3.20436 x 10^-20 Joules.

2. Next, we need to convert the power we want to produce from kW to Joules per second, since power is the rate of energy transfer or conversion. 1 kW is 1000 Joules per second, so 2 kW is 2000 Joules per second.

3. Now, we can calculate the number of fissions required per second. This is given by the total power required divided by the energy released per fission. So, 2000 Joules per second divided by 3.20436 x 10^-20 Joules per fission gives approximately 6.24 x 10^23 fissions per second.

So, to produce 2 kW of power, approximately 6.24 x 10^23 fissions in uranium are required per second.