Must show work/steps on your work page𝑦=𝑥2 −4⁢𝑥+13Find the axis of symmetry:  x =

Sure, let's find the axis of symmetry for the quadratic function $y = x^2 - 4x + 13$.

The general form of a quadratic function is $y = ax^2 + bx + c$. For this function, we have:

• $a = 1$
• $b = -4$
• $c = 13$

The formula to find the axis of symmetry for a quadratic function is given by: $x = -\frac{b}{2a}$

Now, let's substitute the values of $a$ and $b$ into the formula:

1. Identify $a$ and $b$: $a = 1$ $b = -4$

2. Substitute $a$ and $b$ into the formula: $x = -\frac{-4}{2 \cdot 1}$

3. Simplify the expression: $x = -\frac{-4}{2}$ $x = \frac{4}{2}$ $x = 2$

So, the axis of symmetry for the quadratic function $y = x^2 - 4x + 13$ is $x = 2$.