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The oxidation state of chromium in the final product formed by the reaction between KI and acidified potassium dichromate solution is+4+6+2+3

Question

The oxidation state of chromium in the final product formed by the reaction between KI and acidified potassium dichromate solution is

+4
+6
+2
+3

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Solution

The reaction between KI (potassium iodide) and acidified potassium dichromate solution is a redox reaction. In this reaction, the dichromate ion (Cr2O7^2-) is reduced to chromium ion (Cr^3+).

Here are the steps to determine the oxidation state of chromium in the final product:

  1. Write down the half-reaction for the reduction of dichromate ion to chromium ion:

    Cr2O7^2- + 14H^+ + 6e^- -> 2Cr^3+ + 7H2O

  2. From the half-reaction, we can see that each chromium atom gains 3 electrons during the reduction. This means that the oxidation state of chromium decreases from +6 in the dichromate ion to +3 in the chromium ion.

  3. Therefore, the oxidation state of chromium in the final product is +3.

This problem has been solved

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