What is the oxidation number of chromium in the Cr2O72- ion?Question 6Select one:a.+3b.+12c.+7d.+6e.+14
Question
What is the oxidation number of chromium in the Cr2O72- ion?
Question 6
Select one:
- a. +3
- b. +12
- c. +7
- d. +6
- e. +14
Solution
The oxidation number of chromium in the Cr2O7^2- ion can be calculated as follows:
- We know that the overall charge of the ion is -2.
- Oxygen usually has an oxidation number of -2.
- There are 7 oxygen atoms, so the total oxidation number for all oxygen atoms is -14.
- Let's assume the oxidation number of chromium is x. Since there are 2 chromium atoms, the total oxidation number for chromium is 2x.
- The sum of the oxidation numbers of all atoms in a molecule is equal to the charge of the molecule. Therefore, we can set up the following equation: 2x - 14 = -2.
- Solving for x gives us x = +6.
Therefore, the oxidation number of chromium in the Cr2O7^2- ion is +6. So, the correct answer is d. +6.
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