To determine the number of times the loop will run in the given code, we need to analyze the loop condition and the changes made to the variable "digit" within the loop.

1. Initialize the variable "digit" to 0.
2. Check if "digit" is less than 9.
3. If the condition is true, execute the loop body.
4. Multiply the value of "digit" by 2.
5. Decrement the value of "digit" by 1.
6. Repeat steps 2-5 until the condition in step 2 becomes false.

Let's go through the steps:

1. Initialize "digit" to 0.
2. Check if 0 is less than 9. (True)
3. Execute the loop body.
4. Multiply 0 by 2, resulting in 0.
5. Decrement 0 by 1, resulting in -1.
6. Repeat steps 2-5.

Now, let's go through the steps again:

2. Check if -1 is less than 9. (True)
3. Execute the loop body.
4. Multiply -1 by 2, resulting in -2.
5. Decrement -2 by 1, resulting in -3.
6. Repeat steps 2-5.

We can continue this process until the condition in step 2 becomes false. However, since the value of "digit" is always decreasing and it starts at 0, the condition will never become false. Therefore, the loop will run indefinitely.

In conclusion, the given loop will run indefinitely.

Question

To determine the number of times the loop will run in the given code, we need to analyze the loop condition and the changes made to the variable "digit" within the loop.

1. Initialize the variable "digit" to 0.
2. Check if "digit" is less than 9.
3. If the condition is true, execute the loop body.
4. Multiply the value of "digit" by 2.
5. Decrement the value of "digit" by 1.
6. Repeat steps 2-5 until the condition in step 2 becomes false.

Let's go through the steps:

1. Initialize "digit" to 0.
2. Check if 0 is less than 9. (True)
3. Execute the loop body.
4. Multiply 0 by 2, resulting in 0.
5. Decrement 0 by 1, resulting in -1.
6. Repeat steps 2-5.

Now, let's go through the steps again:

2. Check if -1 is less than 9. (True)
3. Execute the loop body.
4. Multiply -1 by 2, resulting in -2.
5. Decrement -2 by 1, resulting in -3.
6. Repeat steps 2-5.

We can continue this process until the condition in step 2 becomes false. However, since the value of "digit" is always decreasing and it starts at 0, the condition will never become false. Therefore, the loop will run indefinitely.

In conclusion, the given loop will run indefinitely.

Knowee AI · Accepted Answer

To determine the number of times the loop will run in the given code, we need to analyze the loop condition and the changes made to the variable "digit" within the loop.

1. Initialize the variable "digit" to 0.
2. Check if "digit" is less than 9.
3. If the condition is true, execute the loop body.
4. Multiply the value of "digit" by 2.
5. Decrement the value of "digit" by 1.
6. Repeat steps 2-5 until the condition in step 2 becomes false.

Let's go through the steps:

1. Initialize "digit" to 0.
2. Check if 0 is less than 9. (True)
3. Execute the loop body.
4. Multiply 0 by 2, resulting in 0.
5. Decrement 0 by 1, resulting in -1.
6. Repeat steps 2-5.

Now, let's go through the steps again:

2. Check if -1 is less than 9. (True)
3. Execute the loop body.
4. Multiply -1 by 2, resulting in -2.
5. Decrement -2 by 1, resulting in -3.
6. Repeat steps 2-5.

We can continue this process until the condition in step 2 becomes false. However, since the value of "digit" is always decreasing and it starts at 0, the condition will never become false. Therefore, the loop will run indefinitely.

In conclusion, the given loop will run indefinitely.

Number of times the loop will run.for(digit = 0;digit < 9; digit++){ digit = digit *2; digit--;}

Question

Number of times the loop will run.

Solution

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Number of times the loop will run.for(digit = 0;digit &lt; 9; digit++){ digit = digit *2; digit--;}