What is the center of the circle given by the equation (x + 5)2 + (y - 8)2 = 1?
Question
Solution 1
The center of the circle given by the equation (x + 5)² + (y - 8)² = 1 is at the point (-5, 8).
Here's the step-by-step explanation:
The general form of the equation of a circle is (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.
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