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What is the r-value of the following data, to three decimal places?xy4 25 98 109 1213 23

Question

What is the r-value of the following data, to three decimal places?

y 4 25 98 109 1213 23

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Solution

To calculate the r-value, also known as the correlation coefficient, we first need to understand the formula for it. The formula is:

r = n(Σxy) - (Σx)(Σy) / sqrt([nΣx^2 - (Σx)^2][nΣy^2 - (Σy)^2])

Where:

  • n is the number of pairs of scores
  • Σ is the sum of
  • x and y are the scores of individual pairs

Given the data:

x: 4, 5, 9, 13 y: 2, 10, 10, 23

We can calculate the following:

Σx = 4 + 5 + 9 + 13 = 31 Σy = 2 + 10 + 10 + 23 = 45 Σxy = 42 + 510 + 910 + 1323 = 8 + 50 + 90 + 299 = 447 Σx^2 = 4^2 + 5^2 + 9^2 + 13^2 = 16 + 25 + 81 + 169 = 291 Σy^2 = 2^2 + 10^2 + 10^2 + 23^2 = 4 + 100 + 100 + 529 = 733 n = 4 (the number of pairs)

Substitute these values into the formula:

r = 4(447) - (31)(45) / sqrt([4291 - (31)^2][4733 - (45)^2]) r = 1788 - 1395 / sqrt([1164 - 961][2932 - 2025]) r = 393 / sqrt([203][907]) r = 393 / sqrt(184021) r = 393 / 429.093

Finally, we get:

r = 0.915

So, the r-value of the given data to three decimal places is 0.915.

This problem has been solved

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